var stdout bytes.Buffer
var stderr bytes.Buffer
cmd := exec.Command(ShellToUse, "-c", command)
cmd.Stdout = &stdout
cmd.Stderr = &stderr
err := cmd.Run()
return err, stdout.String(), stderr.String()
}
func main() {
err, out, errout := Shellout("ls -ltr")
if err != nil {
log.Printf("error: %v\n", err)
}
fmt.Println("--- stdout ---")
fmt.Println(out)
fmt.Println("--- stderr ---")
fmt.Println(errout)
}
以上代码执行后，效果如下：
[root@361way go] go run cmd.go
--- stdout ---
total 24
drwxr-xr-x 6 root root 79 Jun 13 2017 src
-rw-r--r-- 1 root root 752 Aug 19 10:55 login.go
-rw-r--r-- 1 root root 1189 Aug 19 14:29 log.go
-rw-r--r-- 1 root root 623 Aug 19 16:43 cmd.go
-rw-r--r-- 1 root root 538 Aug 19 17:41 cmd2.go
-rw-r--r-- 1 root root 519 Aug 19 21:38 http.go
-rw-r--r-- 1 root root 462 Aug 19 22:29 test.py
--- stderr ---
代码二
package main
import (
"fmt"
"os/exec"
)
func Cmd(cmd string, shell bool) []byte {
if shell {
out, err := exec.Command("bash", "-c", cmd).Output()
if err != nil {
panic("some error found")
}
return out
} else {
out, err := exec.Command(cmd).Output()
if err != nil {
panic("some error found")
}
return out
}
}
func main() {
//cmd := "ls -al"
cmd := "python test.py"
//cmd := "python -V" //没有输出
//cmd := "env"
out := string(Cmd(cmd,true))
//out := string(Cmd(cmd,false))
fmt.Println(out)
}
因为都是调用的exec.Command方法并调用bash shell，本质上并没有什么区别。其也可以正常调用python脚本，但在直接调用python -V命令时没有输出，这点感觉很奇怪。