在golang中复制指针值* a = * b(copy pointer values *a = *b in golang)

a=b

If you want to copy the data structure at B into the data structure at A, do this instead:

*a = *b;

As dmikalova pointed out in the comments below, this merely copies the structs -- but not any data the struct points to. If your struct has a pointer, the data it points to is now shared by the two copies (because it only copied the pointer).

Technically, strings are always pointers, so they are never copied as part of your struct. But because strings are immutable (and Go has Garbage Collection), strings "feel" like they are part of your struct, and you don't have to worry about the low-level string sharing that magically saves you memory without you having to think about it.