如何在golang中按字符a对字符串数组进行排序

sort.Slice()

astrings.Count()stringlen()len()utf8.RuneCountInString()

例如:

in := []string{"aaaasd", "a", "aab", "aaabcd", "ef", "cssssssd", "fdz", "kf", "zc", "lklklklklklklklkl", "l"}

sort.Slice(in, func(i, j int) bool {
    s1, s2 := in[i], in[j]
    count1, count2 := strings.Count(s1, "a"), strings.Count(s2, "a")
    if count1 != count2 {
        return count1 > count2
    }
    return utf8.RuneCountInString(s1) > utf8.RuneCountInString(s2)
})

fmt.Println(in)

这将输出(在Go Playground上试用):

[aaaasd aaabcd aab a lklklklklklklklkl cssssssd fdz ef kf zc l]

asort.SliceStable()sort.Slice()

aless()

它可能是这样的:

// Pre-calculate
type info struct{ count, length int }
calculated := map[string]info{}
for _, s := range in {
    calculated[s] = info{
        count:  strings.Count(s, "a"),
        length: utf8.RuneCountInString(s),
    }
}

sort.Slice(in, func(i, j int) bool {
    inf1, inf2 := calculated[in[i]], calculated[in[j]]
    if inf1.count != inf2.count {
        return inf1.count > inf2.count
    }
    return inf1.length > inf2.length
})

这个输出是相同的.在Go Playground号公路上试试.