golang:逐行读取int字符串的文本文件

问题描述

我正在处理一个包含整数列表作为字符串的输入文件

  10.. 

我选择逐行阅读 ReadString('\ n')方法

以下代码

 行，错误:= inputReader.ReadString('\ n')lineStr:=字符串(行) 

控制台输出(长度和值)

  lineStr％v 4lineStr％v 10 

lineStr的长度为"4"，可能是由于符文编码.

然后我尝试了几种方法将其转换为简单的整数，但没有成功.

Ex1

  num，_:= strconv.ParseUint(lineStr，0，64) 

输出数字0(应为10)

Ex2

  num，_:= strconv.Atoi(lineStr) 

输出数字0(应为10)

Ex3

  num，_:= strconv.Atoi("10") 

输出10(确定)

Ex4

  num，_:= strconv.ParseUint("10"，0，64) 

输出10(确定)

字面意义上的字符串可以，但是文件中的字符串不起作用，这是怎么回事?

预先感谢

从文档:"ReadString读取直到输入中第一次出现delim为止，返回一个字符串，其中包含直到定界符(包括定界符)的数据."

因此，我建议您使用扫描仪，该扫描仪可以像您期望的那样处理这种情况:

  scanner:= bufio.NewScanner(文件)用于扫描仪.Scan(){lineStr:= Scanner.Text()num，_:= strconv.Atoi(lineStr)fmt.Println(lineStr，num)} 

I am dealing with an input file containing a list of integers as a string

10
..

I have choosen to read it line by line with ReadString('\n') method

The following code

line, error := inputReader.ReadString('\n')
lineStr := string(line)

console output (length and value)

lineStr %v 4
lineStr %v 10

lineStr as a length of "4", maybe because of rune encoding.

Then I have tried several way to convert it to simple integer but with no success.

Ex1

num, _ := strconv.ParseUint(lineStr, 0, 64)

ouputs a num of 0 (should be 10)

Ex2

num, _ := strconv.Atoi(lineStr)

ouputs a num of 0 (should be 10)

Ex3

num, _ := strconv.Atoi("10")

ouputs a num of 10 (ok)

Ex4

num, _ := strconv.ParseUint("10", 0, 64)

ouputs a num of 10 (ok)

string in literal are ok but string from file do not work, what is wrong ?

thanks in advance

From the documentation: "ReadString reads until the first occurrence of delim in the input, returning a string containing the data up to and including the delimiter."

Because of this, i suggest you use a scanner, which handles this case like you would expect:

scanner := bufio.NewScanner(file)
for scanner.Scan() {
    lineStr := scanner.Text()
    num, _ := strconv.Atoi(lineStr)
    fmt.Println(lineStr, num)
}

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