substring方法的几种实现

  1. 原生方法,直接使用slice切片实现,但此方法对于包括中文字符就截取错误
s:="abcde"
fmt.Println(s[0:2]);

//输出
//ab

//包含中文的字符串
s2 := "我是中国人"
fmt.Println(s2[0:2])

//输出
//	��
//有乱码呀
rune
//获取source的子串,如果start小于0或者end大于source长度则返回""
//start:开始index,从0开始,包括0
//end:结束index,以end结束,但不包括end
func substring(source string, start int, end int) string {
	var r = []rune(source)
	length := len(r)

	if start < 0 || end > length || start > end {
		return ""
	}

	if start == 0 && end == length {
		return source
	}

	return string(r[start : end])
}

rune
//获取source的子串,如果start小于0或者end大于source长度则返回""
//start:开始index,从0开始,包括0
//end:结束index,以end结束,但不包括end
func substring(source string, start int, end int) string {
	var r = []rune(source)
	length := len(r)

	if start < 0 || end > length || start > end {
		return ""
	}

	if start == 0 && end == length {
		return source
	}

	if start == end {
		return string(r[start])
	}

	var substring = ""
	for i := 0; i < length; i++ {
		if i < start {
			continue
		}
		if i >= end {
			break
		}
		substring += string(r[i])
	}

	return substring
}

//方法二:

func substring(source string, start int, end int) string {

	var substring = ""
	var pos = 0
	for _, c := range source {
		if pos < start {
			pos++
			continue
		}
		if pos >= end {
			break
		}
		pos++
		substring += string(c)
	}

	return substring
}

//方法三

func substring(source string, start int, end int) string {
	var r = []rune(source)
	length := len(r)

	if start < 0 || end > length || start > end {
		return ""
	}

	if start == 0 && end == length {
		return source
	}

	var substring = ""
	for i := start; i < length; i++ {
		substring += string(r[i])
	}

	return substring
}


s := "1人民币哈哈只"
fmt.Printf("%s\n", substring(s, 1, 7))

//输出
//人民币哈哈只

在这里插入图片描述