将 map[interface {}]interface {} 转换为 map[string]string

问题描述

map[interface {}]interface {}

map[interface {}]interface {}

map[string]string

map[string]string

我还需要从数据中生成一个键列表，因为这些是事先不知道的.

I need to generate a list of the keys from the data as well, as those are not known beforehand.

mfmt.Println(m)map[k0:v0 K1:v1 k2:v2 ... ]

mfmt.Println(m)map[k0:v0 K1:v1 k2:v2 ... ]

我怎样才能做 fmt.Println 能做的事?

How can I do what fmt.Println is able to do?

推荐答案

一种处理未知接口的安全方式，只需使用 fmt.Sprintf()

A secure way to process unknown interfaces, just use fmt.Sprintf()

package main

import (
    "fmt"
)

func main() {

    mapInterface := make(map[interface{}]interface{})   
    mapString := make(map[string]string)

    mapInterface["k1"] = 1
    mapInterface[3] = "hello"
    mapInterface["world"] = 1.05

    for key, value := range mapInterface {
        strKey := fmt.Sprintf("%v", key)
        strValue := fmt.Sprintf("%v", value)

        mapString[strKey] = strValue
    }

    fmt.Printf("%#v", mapString)
}

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