golang中字符串拼接方法
- +=
- fmt.sprintf
- append
- buffer.WriteString
- copy
废话不多说,直接上代码看效果
package main import ( "bytes" "fmt" "time" ) func main() { str:="chinese" city:="beijing" // 1. += s:=time.Now() for i:=0;i<100000;i++ { str +=city } e:=time.Since(s) fmt.Println("time cost 1:", e) // 2. fmt.Sprintf str="chinese" city="beijing" s=time.Now() for i:=0;i<100000;i++ { str = fmt.Sprintf("%s%s",str,city) } e=time.Since(s) fmt.Println("time cost 2:", e) //3. buffer.WriteString str="chinese" city="beijing" s=time.Now() var buf= bytes.Buffer{} buf.WriteString(str) for i:=0;i<100000;i++ { buf.WriteString(city) } e=time.Since(s) fmt.Println("time cost 3:", e) //4. append str="chinese" city="beijing" s=time.Now() bstr:=[]byte(str) bcity:=[]byte(city) for i:=0;i<100000;i++ { bstr= append(bstr, bcity...) } e=time.Since(s) fmt.Println("time cost 4:", e) // 5. copy str="chinese" city="beijing" s=time.Now() zstr :=[]byte(str) for i:=0;i<100000;i++ { copy(zstr, city) } e=time.Since(s) fmt.Println("time cost 5:", e) }
最终效果(多次尝试,对比结果都一致):
time cost 1: 3.176250251s time cost 2: 5.347827717s time cost 3: 1.051104ms time cost 4: 769.258µs time cost 5: 323.968µs
效率:copy > append > buf.WriteString > += > fmt.Sprintf
所以请慎用fmt.Sprinf 和 +=