1.简单的string 

fmt.Sprintf()fmt.Sprint()fmt.Sprintln()SSxxx()string

例如： 

 s := fmt.Sprintf("Hi, my name is %s and I'm %d years old.", "Bob", 23) 
s
 Hi, my name is Bob and I'm 23 years old. 
Sprintf()Sprint()
 i := 23 s := fmt.Sprint("[age:", i, "]") // s will be "[age:23]" 
stringstrings.Join()string

在Go游乐场试试这些。

2.复杂的string（文档） 

fmt.Sprintf()
text/templatehtml/templatehtml/templatetext/templatetext/template
templatestring
structmap

例：

例如，假设您想要生成如下所示的电子邮件： 

 Hi [name]! Your account is ready, your user name is: [user-name] You have the following roles assigned: [role#1], [role#2], ... [role#n]

要生成这样的电子邮件消息体，可以使用下面的静态模板： 

 const emailTmpl = `Hi {{.Name}}! Your account is ready, your user name is: {{.UserName}} You have the following roles assigned: {{range $i, $r := .Roles}}{{if ne $i 0}}, {{end}}{{.}}{{end}} `

并提供这样的数据来执行它： 

 data := map[string]interface{}{ "Name": "Bob", "UserName": "bob92", "Roles": []string{"dbteam", "uiteam", "tester"}, } 
io.Writerstringbytes.Bufferio.Writerstring
 t := template.Must(template.New("email").Parse(emailTmpl)) buf := &bytes.Buffer{} if err := t.Execute(buf, data); err != nil { panic(err) } s := buf.String()

这将导致预期产出： 

 Hi Bob! Your account is ready, your user name is: bob92 You have the following roles assigned: dbteam, uiteam, tester

在Go Playground上试试吧。 

os.Stdoutio.Writer
 t := template.Must(template.New("email").Parse(emailTmpl)) if err := t.Execute(os.Stdout, data); err != nil { panic(err) } 
os.Stdout