在过去的几天里,我一直在努力将Java代码迁移到Golang,现在我陷入了困境。这是有效的Java代码:
final Key k = new SecretKeySpec(keyString.getBytes(), "AES");
Cipher c = Cipher.getInstance("AES");
c.init(Cipher.DECRYPT_MODE, k);
final InputStream in = new BufferedInputStream(new FileInputStream(fileNameToDecrypt));
final CipherInputStream instream = new CipherInputStream(in, c);
if (instream.read() != 'B') {
System.out.println("Error");
}
if (instream.read() != 'Z') {
System.out.println("Error");
}
final CBZip2InputStream zip = new CBZip2InputStream(instream);
我在Golang中的实现:
c, _ := aes.NewCipher([]byte(keyString))
// IV must be defined in golang
iv := []byte{0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00}
d := cipher.NewCBCDecrypter(c, iv)
fi, _ := os.Open(fileNameToDecrypt)
stat, _ := fi.Stat()
enc := make([]byte, stat.Size())
dec := make([]byte, stat.Size())
fi.Read(enc)
d.CryptBlocks(dec, enc)
instream := bytes.NewBuffer(dec)
zip := bzip2.NewReader(instream)
到目前为止我所知道的:
这段代码中所有被忽略的错误值_都nil在这段代码中
必须为省略bzip2标头(“ BZ”)CBzip2InputStream,但不能为bzip2.NewReader
从instreamJava和golang中读取的前16个字节是相同的,从第17个字节开始,所有字节由于某种原因而有所不同