我正在读取json中的API响应,并且遇到了json值(字符串,null,bool)内有多个数据类型的问题。另外,一些键的值可以是字符串或空值,这使得将数据读入类型变得更加困难。我想将所有内容都转换为字符串以便于处理。我创建了一个基于谷歌搜索其他例子的类型开关。我想知道这是否是最简单的方法,或者我错过了一个更简单的方法。Golang将json的变量类型转换为字符串
package main
import (
"encoding/json"
"fmt"
"strconv"
)
func main() {
json_byte := []byte(`{"response":[{"t_int":1, "t_bool": true, "t_null_or_string": null}, {"t_int":2, "t_bool": false, "t_null_or_string": "string1"}]}`)
//unmarshal the json to data structure using interface for variable data types
data_json := make(map[string][]map[string]interface{}) //create a structure to hold unmarshalled json
if err := json.Unmarshal(json_byte, &data_json); err != nil {
panic(err)
}
fmt.Println("json_data: ", data_json)
//Iterate over data structure and convert Bool, Int, and Null types to string
var v_conv string // temporary holding for converted string values
data_map := make(map[string]string) // temporary holding for converted maps
data_final := make([]map[string]string, 0, 100) // final holding for data converted to strings
for _, v := range data_json { //v is the value of the "response": key which is a slice of maps
for _, v2 := range v { //v2 is one of the maps in the slice of maps
for k3, v3 := range v2 { //k3 and v3 are the keys and values inside the map
fmt.Println("k3: ", k3, "v3: ", v3)
switch v_type := v3.(type) {
case nil:
v_conv = ""
case bool:
v_conv = strconv.FormatBool(v3.(bool))
case int:
v_conv = strconv.Itoa(v3.(int))
case string:
v_conv = v3.(string)
case float64:
v_conv = strconv.FormatFloat(v3.(float64), 'f', 0, 64)
default:
fmt.Println("vtype unknown: ", v_type) //have to use v_type since it is declared
v_conv = ""
}
data_map[k3] = v_conv //append a new map key/value pair both as strings
fmt.Println("data_map: ", data_map)
}
data_final = append(data_final, data_map) // after each cycle through the loop append the map to the new list
fmt.Println("data_final: ", data_final)
}
}
}
最终格式所期望的地图 [{ “T_INT”: “1”, “t_bool”: “真”, “t_null_string”: “的切片” }, { “T_INT “: “2”, “t_bool”: “假”, “t_null_string”: “字符串1” }]
2016-12-06 Ryan D.